Titration Curve For Weak Base And Strong Acid
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Nov 05, 2025 · 11 min read
Table of Contents
The titration curve for a weak base and strong acid unveils the intricate dance of proton transfer, revealing key characteristics about the solution's composition and behavior throughout the titration process. Understanding this curve is crucial for analytical chemistry, allowing for precise determination of unknown concentrations and a deeper comprehension of acid-base chemistry.
Understanding Weak Base - Strong Acid Titrations
Weak base - strong acid titrations involve the reaction between a weak base, which only partially dissociates in water, and a strong acid, which completely dissociates. This reaction results in the formation of the conjugate acid of the weak base. The titration curve plots the pH of the solution against the volume of the strong acid added. The shape of this curve, particularly the equivalence point and buffering region, provides valuable information about the weak base.
Key Components of the Titration Curve
- Initial pH: The starting pH is determined by the concentration of the weak base and its base dissociation constant (K<sub>b</sub>).
- Buffering Region: This region demonstrates the solution's resistance to pH change upon the addition of small amounts of acid. It arises because the weak base and its conjugate acid are both present in significant quantities.
- Half-Equivalence Point: At this point, the concentration of the weak base is equal to the concentration of its conjugate acid. The pH at the half-equivalence point is equal to the pK<sub>a</sub> of the conjugate acid. This is derived from the Henderson-Hasselbalch equation: pH = pK<sub>a</sub> + log([Base]/[Acid]). When [Base] = [Acid], log([Base]/[Acid]) = log(1) = 0, therefore pH = pK<sub>a</sub>.
- Equivalence Point: This is the point where the moles of acid added are stoichiometrically equivalent to the moles of base initially present. Unlike strong acid-strong base titrations, the pH at the equivalence point is not 7. It's acidic because only the conjugate acid of the weak base is present. This conjugate acid will react with water (hydrolyze) to produce H<sup>+</sup> ions, lowering the pH.
- Excess Acid Region: After the equivalence point, the pH is determined by the excess strong acid added to the solution. The curve approaches the shape of a strong acid titration.
Steps to Constructing a Titration Curve
Creating a titration curve for a weak base and strong acid requires careful calculations at different stages of the titration. Here's a step-by-step guide:
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Initial pH Calculation:
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Determine the initial concentration of the weak base (B).
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Set up an ICE (Initial, Change, Equilibrium) table to calculate the hydroxide ion concentration ([OH<sup>-</sup>]) using the K<sub>b</sub> value for the weak base:
B(aq) + H2O(l) <=> BH+(aq) + OH-(aq)B BH+ OH- Initial [B]₀ 0 0 Change -x +x +x Equilibrium [B]₀-x x x -
Write the K<sub>b</sub> expression: K<sub>b</sub> = [BH<sup>+</sup>][OH<sup>-</sup>] / [B]
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Solve for x ([OH<sup>-</sup>]). If K<sub>b</sub> is small enough, you can often assume that x is negligible compared to the initial concentration of the base and simplify the calculation.
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Calculate the pOH: pOH = -log[OH<sup>-</sup>]
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Calculate the pH: pH = 14 - pOH
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-
pH Before the Equivalence Point (Buffering Region):
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Calculate the moles of acid added.
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Determine the moles of weak base (B) remaining and the moles of its conjugate acid (BH<sup>+</sup>) formed.
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Use the Henderson-Hasselbalch equation to calculate the pH:
pH = pK<sub>a</sub> + log([B]/[BH<sup>+</sup>])
Where pK<sub>a</sub> = 14 - pK<sub>b</sub>
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Repeat this calculation for several points before the equivalence point.
-
-
pH at the Half-Equivalence Point:
- At the half-equivalence point, [B] = [BH<sup>+</sup>].
- Therefore, pH = pK<sub>a</sub>. This allows you to directly determine the pK<sub>a</sub> of the conjugate acid of the weak base from the titration curve.
-
pH at the Equivalence Point:
-
At the equivalence point, all the weak base has been converted to its conjugate acid (BH<sup>+</sup>).
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Calculate the concentration of BH<sup>+</sup> considering the total volume of the solution.
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BH<sup>+</sup> will act as a weak acid and hydrolyze water:
BH+(aq) + H2O(l) <=> B(aq) + H3O+(aq) -
Set up an ICE table and calculate the hydronium ion concentration ([H<sub>3</sub>O<sup>+</sup>]) using the K<sub>a</sub> value for BH<sup>+</sup>: K<sub>a</sub> = K<sub>w</sub> / K<sub>b</sub>
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Calculate the pH: pH = -log[H<sub>3</sub>O<sup>+</sup>]
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pH After the Equivalence Point:
- Calculate the moles of excess strong acid added.
- Calculate the concentration of the excess strong acid in the total volume of the solution.
- Since the strong acid completely dissociates, [H<sub>3</sub>O<sup>+</sup>] equals the concentration of the excess strong acid.
- Calculate the pH: pH = -log[H<sub>3</sub>O<sup>+</sup>]
- Repeat this calculation for several points after the equivalence point.
-
Plot the Data:
- Plot the calculated pH values against the corresponding volume of strong acid added.
- The resulting graph is the titration curve for the weak base and strong acid.
Example: Titration of Ammonia (NH<sub>3</sub>) with Hydrochloric Acid (HCl)
Let's consider the titration of 50.0 mL of 0.10 M ammonia (NH<sub>3</sub>, a weak base, K<sub>b</sub> = 1.8 x 10<sup>-5</sup>) with 0.10 M hydrochloric acid (HCl, a strong acid).
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Initial pH:
- NH<sub>3</sub>(aq) + H<sub>2</sub>O(l) <=> NH<sub>4</sub><sup>+</sup>(aq) + OH<sup>-</sup>(aq)
- K<sub>b</sub> = [NH<sub>4</sub><sup>+</sup>][OH<sup>-</sup>] / [NH<sub>3</sub>] = 1.8 x 10<sup>-5</sup>
- Using the ICE table, we get: 1.8 x 10<sup>-5</sup> = x<sup>2</sup> / (0.10 - x)
- Assuming x is small compared to 0.10, we get: 1.8 x 10<sup>-5</sup> ≈ x<sup>2</sup> / 0.10
- x = [OH<sup>-</sup>] ≈ 1.34 x 10<sup>-3</sup> M
- pOH = -log(1.34 x 10<sup>-3</sup>) = 2.87
- pH = 14 - 2.87 = 11.13
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pH Before the Equivalence Point (e.g., after adding 25.0 mL of HCl):
- Moles of NH<sub>3</sub> initially: (0.050 L)(0.10 mol/L) = 0.0050 mol
- Moles of HCl added: (0.025 L)(0.10 mol/L) = 0.0025 mol
- Moles of NH<sub>3</sub> remaining: 0.0050 mol - 0.0025 mol = 0.0025 mol
- Moles of NH<sub>4</sub><sup>+</sup> formed: 0.0025 mol
- pH = pK<sub>a</sub> + log([NH<sub>3</sub>]/[NH<sub>4</sub><sup>+</sup>])
- pK<sub>b</sub> = -log(1.8 x 10<sup>-5</sup>) = 4.74
- pK<sub>a</sub> = 14 - 4.74 = 9.26
- pH = 9.26 + log(0.0025/0.0025) = 9.26
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pH at the Half-Equivalence Point:
- pH = pK<sub>a</sub> = 9.26 (when 1/2 of the NH<sub>3</sub> has been converted to NH<sub>4</sub><sup>+</sup>)
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pH at the Equivalence Point:
- Volume of HCl required to reach equivalence: 50.0 mL (since the concentrations are equal)
- Moles of NH<sub>4</sub><sup>+</sup> formed: 0.0050 mol
- Total volume: 50.0 mL + 50.0 mL = 100.0 mL = 0.100 L
- [NH<sub>4</sub><sup>+</sup>] = 0.0050 mol / 0.100 L = 0.050 M
- NH<sub>4</sub><sup>+</sup>(aq) + H<sub>2</sub>O(l) <=> NH<sub>3</sub>(aq) + H<sub>3</sub>O<sup>+</sup>(aq)
- K<sub>a</sub> = K<sub>w</sub> / K<sub>b</sub> = (1.0 x 10<sup>-14</sup>) / (1.8 x 10<sup>-5</sup>) = 5.56 x 10<sup>-10</sup>
- Using the ICE table, we get: 5.56 x 10<sup>-10</sup> = x<sup>2</sup> / (0.050 - x)
- Assuming x is small compared to 0.050, we get: 5.56 x 10<sup>-10</sup> ≈ x<sup>2</sup> / 0.050
- x = [H<sub>3</sub>O<sup>+</sup>] ≈ 5.27 x 10<sup>-6</sup> M
- pH = -log(5.27 x 10<sup>-6</sup>) = 5.28
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pH After the Equivalence Point (e.g., after adding 75.0 mL of HCl):
- Moles of HCl added: (0.075 L)(0.10 mol/L) = 0.0075 mol
- Moles of excess HCl: 0.0075 mol - 0.0050 mol = 0.0025 mol
- Total volume: 50.0 mL + 75.0 mL = 125.0 mL = 0.125 L
- [H<sub>3</sub>O<sup>+</sup>] = 0.0025 mol / 0.125 L = 0.020 M
- pH = -log(0.020) = 1.70
By plotting these calculated pH values against the corresponding volumes of HCl added, we obtain the titration curve for the titration of ammonia with hydrochloric acid. This curve will show a gradual decrease in pH, a buffering region around pH 9.26, and an equivalence point at pH 5.28.
Factors Affecting the Titration Curve
Several factors can influence the shape and characteristics of the titration curve:
- K<sub>b</sub> Value: A smaller K<sub>b</sub> value (weaker base) will result in a lower initial pH and a less distinct buffering region. The pH at the equivalence point will also be lower (more acidic).
- Concentration of the Base and Acid: Higher concentrations will generally lead to sharper changes in pH near the equivalence point, making it easier to determine the equivalence point accurately. However, the initial pH will also be affected by the base concentration.
- Temperature: Temperature changes can affect the K<sub>b</sub> value and the K<sub>w</sub> value of water, which in turn can influence the pH at various points on the titration curve.
Applications of Titration Curves
Titration curves are essential tools in analytical chemistry with numerous applications:
- Determining the Concentration of Unknown Solutions: By accurately determining the equivalence point, the concentration of an unknown weak base solution can be calculated using stoichiometry.
- Determining the K<sub>b</sub> Value of a Weak Base: The K<sub>b</sub> value can be determined experimentally by finding the pH at the half-equivalence point. This provides valuable information about the strength of the weak base.
- Selecting Appropriate Indicators: Titration curves help in selecting appropriate indicators for acid-base titrations. The indicator should change color within the steep portion of the curve around the equivalence point to provide an accurate endpoint determination.
- Studying Acid-Base Equilibria: Titration curves provide insights into the behavior of weak acids and weak bases in solution, including buffering capacity and the effects of pH on chemical reactions.
- Quality Control: Titration curves are used in various industries for quality control purposes, such as determining the acidity or basicity of food products, pharmaceuticals, and environmental samples.
Limitations of Titration Curves
While titration curves are powerful tools, they also have limitations:
- Subjectivity in Equivalence Point Determination: Determining the exact equivalence point can sometimes be subjective, especially if the pH change near the equivalence point is gradual.
- Interference from Other Substances: The presence of other acidic or basic substances in the sample can interfere with the titration and affect the accuracy of the results.
- Time-Consuming: Constructing a titration curve can be time-consuming, especially if multiple data points are required for accurate analysis.
- Requires Accurate Measurements: Accurate measurements of volume and concentration are essential for obtaining reliable titration curves. Any errors in these measurements will propagate through the calculations and affect the results.
Titration Curve vs. Strong Base and Weak Acid
The titration curve of a strong base and weak acid is essentially a mirror image of the weak base and strong acid titration curve. Here are the key differences:
- Initial pH: The starting pH is high due to the presence of the strong base.
- Equivalence Point: The pH at the equivalence point is above 7 because the conjugate base of the weak acid hydrolyzes water, generating OH<sup>-</sup> ions.
- Buffering Region: The buffering region is located at a higher pH range.
- Shape of the Curve: The curve starts at a high pH and gradually decreases as the weak acid is added.
Understanding these differences is crucial for correctly interpreting the titration curve and obtaining accurate results.
Conclusion
The titration curve for a weak base and strong acid is a powerful tool for understanding and quantifying acid-base reactions. By carefully analyzing the shape of the curve, the equivalence point, and the buffering region, valuable information about the weak base can be obtained. This knowledge is essential for various applications in analytical chemistry, quality control, and research. While there are limitations to consider, the benefits of using titration curves for acid-base analysis are undeniable. Mastering the principles of titration curves empowers chemists and scientists to accurately determine unknown concentrations, study acid-base equilibria, and make informed decisions in a wide range of fields.
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