Surface Area Of A Cylinder Questions

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Nov 18, 2025 · 11 min read

Surface Area Of A Cylinder Questions
Surface Area Of A Cylinder Questions

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    The surface area of a cylinder, a fundamental concept in geometry, extends beyond simple formulas, offering a gateway to understanding real-world applications and problem-solving strategies. From calculating the material needed to construct a cylindrical tank to optimizing packaging designs, a firm grasp of surface area principles is invaluable.

    Understanding the Surface Area of a Cylinder

    The surface area of a cylinder refers to the total area covering its exterior. Envision a can of soup: the surface area encompasses the curved side, the top, and the bottom. To calculate this, we break it down into simpler geometric shapes.

    Components of Surface Area

    • Two Circles: A cylinder has two circular ends (top and bottom), each with an area of πr², where r is the radius of the circle.

    • Lateral Surface: This is the curved surface connecting the two circles. Imagine unrolling the label of a soup can; it forms a rectangle. The height of the rectangle is the height (h) of the cylinder, and the width is the circumference of the circular base (2πr). Therefore, the lateral surface area is 2πrh.

    The Formula

    The total surface area (TSA) of a cylinder is the sum of the areas of its two circular ends and its lateral surface:

    TSA = 2πr² + 2πrh

    This formula serves as the foundation for solving various problems related to cylindrical objects.

    Common Surface Area of a Cylinder Questions and Solutions

    Let's dive into different types of surface area of a cylinder questions you might encounter, along with detailed solutions.

    Basic Calculation Problems

    These problems directly apply the formula, requiring you to plug in the given values for radius and height.

    Question 1: A cylinder has a radius of 5 cm and a height of 10 cm. Calculate its surface area.

    Solution:

    1. Identify the given values:
      • Radius (r) = 5 cm
      • Height (h) = 10 cm
    2. Apply the formula: TSA = 2πr² + 2πrh TSA = 2π(5 cm)² + 2π(5 cm)(10 cm) TSA = 2π(25 cm²) + 2π(50 cm²) TSA = 50π cm² + 100π cm² TSA = 150π cm²
    3. Approximate the answer: TSA ≈ 150 * 3.14159 cm² TSA ≈ 471.24 cm²

    Answer: The surface area of the cylinder is approximately 471.24 cm².

    Question 2: Find the surface area of a cylinder with a diameter of 12 inches and a height of 8 inches.

    Solution:

    1. Identify the given values:
      • Diameter = 12 inches, so radius (r) = Diameter / 2 = 6 inches
      • Height (h) = 8 inches
    2. Apply the formula: TSA = 2πr² + 2πrh TSA = 2π(6 inches)² + 2π(6 inches)(8 inches) TSA = 2π(36 inches²) + 2π(48 inches²) TSA = 72π inches² + 96π inches² TSA = 168π inches²
    3. Approximate the answer: TSA ≈ 168 * 3.14159 inches² TSA ≈ 527.79 inches²

    Answer: The surface area of the cylinder is approximately 527.79 inches².

    Problems Involving the Lateral Surface Area

    These problems focus on the curved surface of the cylinder.

    Question 3: The lateral surface area of a cylinder is 220 cm², and its height is 11 cm. Find the radius of the base.

    Solution:

    1. Identify the given values:
      • Lateral Surface Area = 220 cm²
      • Height (h) = 11 cm
    2. Use the lateral surface area formula: Lateral Surface Area = 2πrh 220 cm² = 2πr(11 cm)
    3. Solve for r: 220 cm² = 22πr cm r = (220 cm²) / (22π cm) r = 10/π cm
    4. Approximate the answer: r ≈ 10 / 3.14159 cm r ≈ 3.18 cm

    Answer: The radius of the base is approximately 3.18 cm.

    Question 4: A cylindrical tank has a height of 15 meters and a circumference of 25 meters. Calculate the area of the sheet metal required to make the tank (ignoring overlaps).

    Solution:

    1. Identify the given values:
      • Height (h) = 15 meters
      • Circumference = 25 meters
    2. Find the radius using the circumference formula: Circumference = 2πr 25 meters = 2πr r = 25 / (2π) meters
    3. Calculate the lateral surface area: Lateral Surface Area = 2πrh Lateral Surface Area = (2π) * (25 / (2π) meters) * (15 meters) Lateral Surface Area = 25 meters * 15 meters Lateral Surface Area = 375 m²
    4. Calculate the area of the two circular ends: Area of one circle = πr² = π * (25 / (2π))² = 625 / (4π) m² Area of two circles = 2 * (625 / (4π)) = 625 / (2π) m²
    5. Calculate the total surface area: TSA = Lateral Surface Area + Area of two circles TSA = 375 m² + 625 / (2π) m² TSA ≈ 375 m² + (625 / (2 * 3.14159)) m² TSA ≈ 375 m² + 99.47 m² TSA ≈ 474.47 m²

    Answer: Approximately 474.47 m² of sheet metal is required to make the tank.

    Problems Involving Total Surface Area and One Dimension

    These problems provide the total surface area and either the radius or height, requiring you to solve for the missing dimension.

    Question 5: The surface area of a cylinder is 300π cm², and its radius is 6 cm. Find the height of the cylinder.

    Solution:

    1. Identify the given values:
      • TSA = 300π cm²
      • Radius (r) = 6 cm
    2. Apply the formula and solve for h: TSA = 2πr² + 2πrh 300π cm² = 2π(6 cm)² + 2π(6 cm)h 300π cm² = 2π(36 cm²) + 12πh cm 300π cm² = 72π cm² + 12πh cm 300π cm² - 72π cm² = 12πh cm 228π cm² = 12πh cm h = (228π cm²) / (12π cm) h = 19 cm

    Answer: The height of the cylinder is 19 cm.

    Question 6: A cylinder has a surface area of 600 cm² and a height of 10 cm. Find the radius of the base. (This problem requires solving a quadratic equation)

    Solution:

    1. Identify the given values:
      • TSA = 600 cm²
      • Height (h) = 10 cm
    2. Apply the formula and solve for r: TSA = 2πr² + 2πrh 600 cm² = 2πr² + 2πr(10 cm) 600 cm² = 2πr² + 20πr cm Divide both sides by 2π: 300/π cm² = r² + 10r cm Rearrange into a quadratic equation: r² + 10r - 300/π = 0
    3. Solve the quadratic equation using the quadratic formula: r = (-b ± √(b² - 4ac)) / 2a Where a = 1, b = 10, and c = -300/π r = (-10 ± √(10² - 4 * 1 * (-300/π))) / 2 r = (-10 ± √(100 + 1200/π)) / 2 r = (-10 ± √(100 + 381.97)) / 2 r = (-10 ± √481.97) / 2 r = (-10 ± 21.95) / 2 We have two possible solutions: r₁ = (-10 + 21.95) / 2 = 11.95 / 2 = 5.975 cm r₂ = (-10 - 21.95) / 2 = -31.95 / 2 = -15.975 cm (We discard this as radius cannot be negative)

    Answer: The radius of the base is approximately 5.975 cm.

    Ratio Problems

    These problems involve ratios between the radius, height, and surface area.

    Question 7: The radius and height of a cylinder are in the ratio 2:3. If the surface area is 462 cm², find the radius and height. (Assume π = 22/7)

    Solution:

    1. Express radius and height in terms of a variable: Let the radius be 2x and the height be 3x.
    2. Apply the formula: TSA = 2πr² + 2πrh 462 cm² = 2 * (22/7) * (2x)² + 2 * (22/7) * (2x) * (3x) 462 cm² = (44/7) * 4x² + (44/7) * 6x² 462 cm² = (176/7)x² + (264/7)x² 462 cm² = (440/7)x²
    3. Solve for x²: x² = (462 cm² * 7) / 440 x² = 3234 / 440 x² = 7.35
    4. Solve for x: x = √7.35 x ≈ 2.71
    5. Find the radius and height: Radius (r) = 2x ≈ 2 * 2.71 ≈ 5.42 cm Height (h) = 3x ≈ 3 * 2.71 ≈ 8.13 cm

    Answer: The radius is approximately 5.42 cm, and the height is approximately 8.13 cm.

    Question 8: Two cylinders have the same height. The ratio of their radii is 1:2. What is the ratio of their surface areas?

    Solution:

    1. Define variables: Let the height of both cylinders be h. Let the radius of the first cylinder be r, and the radius of the second cylinder be 2r.
    2. Calculate the surface areas: Surface Area of Cylinder 1 (SA₁) = 2πr² + 2πrh Surface Area of Cylinder 2 (SA₂) = 2π(2r)² + 2π(2r)h = 2π(4r²) + 4πrh = 8πr² + 4πrh
    3. Find the ratio SA₁ : SA₂: SA₁ / SA₂ = (2πr² + 2πrh) / (8πr² + 4πrh) Factor out 2πr from both the numerator and the denominator: SA₁ / SA₂ = 2πr(r + h) / 2πr(4r + 2h) Cancel out the common factor 2πr: SA₁ / SA₂ = (r + h) / (4r + 2h)
    4. The ratio depends on the values of r and h. We cannot get a numerical answer without more information. Let's assume r=h to simplify: SA₁ / SA₂ = (r + r) / (4r + 2r) = 2r / 6r = 1/3

    Answer: If we assume r=h, the ratio of their surface areas is 1:3. Without more information about the relationship between r and h, we can only express the ratio as (r + h) / (4r + 2h).

    Real-World Application Problems

    These problems involve applying the surface area concept to practical scenarios.

    Question 9: A company wants to manufacture cylindrical cans that hold 500 ml of liquid. If they want to minimize the amount of material used (i.e., minimize the surface area), what should the dimensions (radius and height) of the can be? (1 ml = 1 cm³)

    Solution:

    1. Establish the relationship between volume and dimensions: Volume (V) = πr²h = 500 cm³ Therefore, h = 500 / (πr²)
    2. Express the surface area in terms of r: TSA = 2πr² + 2πrh Substitute h = 500 / (πr²) into the TSA equation: TSA = 2πr² + 2πr(500 / (πr²)) TSA = 2πr² + 1000/r
    3. Minimize the surface area using calculus: To find the minimum surface area, we need to find the critical points of the TSA function by taking its derivative with respect to r and setting it equal to zero: d(TSA)/dr = 4πr - 1000/r² Set d(TSA)/dr = 0: 4πr - 1000/r² = 0 4πr = 1000/r² 4πr³ = 1000 r³ = 1000 / (4π) r³ = 250 / π r = ∛(250 / π) r ≈ ∛(79.577) r ≈ 4.30 cm
    4. Find the height: h = 500 / (πr²) h = 500 / (π * (4.30)²) h = 500 / (π * 18.49) h ≈ 500 / 58.09 h ≈ 8.61 cm

    Answer: To minimize the material used, the can should have a radius of approximately 4.30 cm and a height of approximately 8.61 cm.

    Question 10: A cylindrical water tank with a diameter of 8 feet and a height of 12 feet needs to be painted. One gallon of paint covers 350 square feet. How many gallons of paint are needed to paint the entire tank, including the top and bottom?

    Solution:

    1. Calculate the radius: Diameter = 8 feet, so radius (r) = 8 / 2 = 4 feet
    2. Calculate the surface area: TSA = 2πr² + 2πrh TSA = 2π(4 feet)² + 2π(4 feet)(12 feet) TSA = 2π(16 feet²) + 2π(48 feet²) TSA = 32π feet² + 96π feet² TSA = 128π feet² TSA ≈ 128 * 3.14159 feet² TSA ≈ 402.12 feet²
    3. Calculate the number of gallons needed: Gallons needed = Total surface area / Coverage per gallon Gallons needed = 402.12 feet² / 350 feet²/gallon Gallons needed ≈ 1.15 gallons

    Answer: Approximately 1.15 gallons of paint are needed to paint the entire tank. Since you can't buy a fraction of a gallon, you would need to purchase 2 gallons.

    Advanced Concepts and Considerations

    • Open Cylinders: If a cylinder is open at one end (like a pipe), you only calculate the area of one circular base. The formula becomes: TSA = πr² + 2πrh

    • Hollow Cylinders: These consist of two concentric cylinders. To find the surface area, calculate the surface area of both the inner and outer cylinders and add them.

    • Units: Always pay close attention to units. Ensure consistency throughout the calculation. Convert all measurements to the same unit before applying the formulas.

    • Approximations: When using π (pi), remember it's an irrational number. Use an appropriate number of decimal places for your calculation based on the required precision.

    Tips for Solving Cylinder Surface Area Problems

    • Draw a Diagram: Visualizing the problem can help you understand the given information and the relationships between different parts of the cylinder.
    • Identify Givens and Unknowns: Clearly list the values provided in the problem and what you need to find.
    • Choose the Correct Formula: Ensure you are using the appropriate formula based on the problem's context (total surface area, lateral surface area, open cylinder, etc.).
    • Show Your Work: Writing down each step helps you avoid errors and makes it easier to track your progress.
    • Check Your Answer: Does your answer make sense in the context of the problem? Are the units correct?

    Conclusion

    Mastering the surface area of a cylinder unlocks a range of practical applications, from engineering and manufacturing to everyday problem-solving. By understanding the underlying principles, practicing with various question types, and employing a systematic approach, you can confidently tackle any cylinder surface area challenge. Remember to visualize the problem, choose the correct formula, and pay attention to detail. With consistent practice, you'll find these calculations become second nature.

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